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"Scientific American Supplement, No. 312, December 24, 1881"


15,772 x 772[2] = 12,175,984 foot pounds of energy is occluded in the
static caloric contained in one pound of such coal.
[Footnote 2: Dr. Joule--foot pounds in one unit.]
A horse-power is estimated as capable of raising 33,000 pounds one
foot high per minute, and for this reason it is termed 33,000 foot
pounds per minute. So we have 33,000 x 60 = 1,980,000 foot pounds per
hour, as a horse-power.
The best class of _compound condensing_ engines,[3] with all the
modern improvements, require 1.828 pounds of coal per 1 h.p. per hour.
Thus we have--
12,175,984 x 1.828 .................22,257,699
Foot pounds in one h.p. .............1,980,000
----------
Foot pounds lost per h.p. ..........20,277,699
Per cent utilized per h.p. ..............8.94
Per cent lost per h.p. .................91.06
------
100.00
[Footnote 3: "American Engineer," Vol. II., No. 10, page 182.]
In the ordinary practice of stationary non-condensing engines, from
three to four pounds of coal are required per horse-power per hour.
Now, taking the best of this class at 3 pounds, we have--
12,175,984 x 3 = 36,527,952
One h.


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